Tugas
A. alamat subnet mask
B. alamat subnet
C. alamat broadcast
D. jumlah subnet
E. alamat subnet ke-3
dari alamat sebagai berikut :
1. 198.53.67.0/30
2. 202.151.37.0/26
1.
198.53.67.0/30
11111111.11111111.11111111.11111100(255.255.255.252)
Jumlah subnet=26 =64
subnet
Jumlah host persubnet=2 2 -2=2 subnet
Host dan broadcast yang vaild?
Subnet
|
198.53.67.0
|
198.53.67.4
|
198.53.67.8
|
198.53.67.12
|
Host pertama
|
198.53.67.1
|
198.53.67.5
|
198.53.67.9
|
198.53.67.13
|
Host terakhir
|
198.53.67.2
|
198.53.67.66
|
198.53.67.130
|
198.53.67.194
|
Broadcast
|
198.53.67.3
|
198.53.67.67
|
198.53.67.131
|
198.53.67.195
|
A.
Alamat subnet maks=255.255 255.252
B.
Alamat subnet=(198.53.67.0),(198.53.67.4),(198.53.67.8),(198.53.67.12)dst(198.53.67.252)
C.
Alamat broadcast=(198.53.67.3),(198.53.67.67),(198.53.67.131),(198.53.67.195)dst(198.53.67.252)
D.
Jumlah host yang digunakan =jumlah host X jumlah
subnet
=2 X 64
=128
E.
Alamat subnet ke-3=(198.53.67.8)
2.
202.151.37.0/26
11111111.11111111.11111111.110000(255.255.255.192)
Jumlah subnet=22 =4
subnet
Jumlah host persubnet=22 _ 2
=2 subnet
Blok subnet 256-192 =64,subnet lengkapnya adalah 0,64,128,192
Hos dan broadcast yang vaild?
Subnet
|
202.151.37.0
|
202.151.37.64
|
202.151.37.128
|
202.151.37.192
|
Host pertama
|
202.151.37.1
|
202.151.37.65
|
202.151.37.129
|
202.151.37.193
|
Host terakhir
|
202.151.37.62
|
202.151.37.126
|
202.151.37.190
|
202.151.37.254
|
Broadcast
|
202.151.37.63
|
202.151.37.127
|
202.151.37.191
|
202.151.37.255
|
A.
Alamat subenet mask = 255.255.255.192
B.
Alamat subnet =(202.151.37.0),(202.151.37.64),(202.151.37.128),(202.151.37.192)
C.
Alamat broadcast =
(202.151.37.63),(202.151.37.127),(202.151.37.191),(202.151.37.255)
D.
Jumlah host yang di gunakan = jumlah host x jumlah subnet
= 2 X 4
= 8
E. Alamat subnet ke-3 = 202.151.37.128
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